 # Quadratic Equations Question for SBI PO, Clerk and IBPS Exam ## Quadratic Equations Question for SBI PO, Clerk and IBPS Exam

Directions (Q.1-5): In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer.

Q.1

I. 35x2 – 11x – 6 = 0               II. 5y2 – 23y + 12 = 0

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

Q.2

I. x2 × 2161/3 = √576 x 22                II. y3 – √1225 = √841

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

Q.3

I. 72x2 + 59x + 12 = 0               II. 44y2 + 67y + 15 = 0

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

Q.4

I. (
 x 4
– 2) (
 x 3
– 5) = 0
II. √ × y2 =
 49 × 3431/3 √7         .

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

Q.5

I. √484 x (1331)1/3 x X = 5082

II.
 √ y 21
+
 √ y 7
= √ 16

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

Answer 1. (C) if x ≤ y

Explanation:

I. 35x2 – 11x – 6 = 0

35x2 – 21x + 10x – 6 = 0

7x (5x – 3) + 2 (5x – 3) = 0

(5x – 3) (7x + 2) = 0

x = 3/5, –2/7

II. 5y2 – 23y + 12 = 0

5y2 – 20y – 3y + 12 = 0

5y (y – 4) – 3 (y – 4) = 0

(y – 4) (5y – 3) = 0

y = 4, 3/5

Answer 2. (C) if x ≤ y

Explanation:

I. x2 × 2161/3 = √576 x 22

x2 × 6 = 24 x 4

x2 = 16

x = ± 4

II. y3 – √1225 = √841

y3 – 35 = 29

y3 = 29 + 35

y3 = 64

y = 4

Answer 3. (E) if x = y or relationship between x and y can’t be established

Explanation:

I. 72x2 + 59x + 12 = 0

72x2 + 27x + 32x + 12 = 0

9x (8x + 3) + 4 (8x + 3) = 0

(8x + 3) (9x + 4) = 0

x = – 3/8, – 4/9

II. 44y2 + 67y + 15 = 0

44y2 + 55y + 12y + 15 = 0

11y (4y + 5) + 3 (4y + 5) = 0

(11y + 3) (4y + 5) = 0

y = – 3/11, – 5/4

Answer 4. (B) if x > y

Explanation:

I. (
 x 4
– 2) (
 x 3
– 5) = 0
I. (
 x -8 4
) (
 x – 15 3
) = 0

(x – 8) (x – 15) = 0

x = 8, 15

II. √ × y2 =
 49 × 3431/3 √7         .
II. y1/2 × y2 =
 72 × 7 71/2  .

y5/2 = 72 + 1 – 1/2

y5/2 = 75/2

y = 7

Answer 5. (A) if x < y

Explanation:

I. √484 x 13311/3 x X= 5082

22 x 11 x X = 5082

x = 21

II.
 √ y 21
+
 √ y 7
= √ 16
 √ y  + 3√ y 2
= 4

4√ y  = 84

y  = 21

y = 441