Quadratic Equations Question for SBI PO, Clerk and IBPS Exam

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Quadratic Equations Question for SBI PO, Clerk and IBPS Exam

Quadratic Equations Question for SBI PO, Clerk and IBPS Exam

Directions (Q.1-5): In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer.

Q.1 

I. 35x2 – 11x – 6 = 0               II. 5y2 – 23y + 12 = 0

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

 

Q.2

I. x2 × 2161/3 = √576 x 22                II. y3 – √1225 = √841

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

 

Q.3 

I. 72x2 + 59x + 12 = 0               II. 44y2 + 67y + 15 = 0

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

 

Q.4

[su_table responsive=”yes” class=”code”]

I. (
x
 4
 – 2) (
x
 3
 – 5) = 0

[/su_table]

[su_table responsive=”yes” class=”code”]

II. √ × y2 =
49 × 3431/3
      √7         .

[/su_table]

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

 

Q.5

I. √484 x (1331)1/3 x X = 5082

[su_table responsive=”yes” class=”code”]

II.
 √ y 
 21
 +
 √ y 
  7
 = √ 16

[/su_table]

(A) if x < y

(B) if x > y

(C) if x ≤ y

(D) if x ≥ y

(E) if x = y or relationship between x and y can’t be established

 

Answer 1. (C) if x ≤ y

Explanation:

I. 35x2 – 11x – 6 = 0

35x2 – 21x + 10x – 6 = 0

7x (5x – 3) + 2 (5x – 3) = 0

(5x – 3) (7x + 2) = 0

x = 3/5, –2/7

 

II. 5y2 – 23y + 12 = 0

5y2 – 20y – 3y + 12 = 0

5y (y – 4) – 3 (y – 4) = 0

(y – 4) (5y – 3) = 0

y = 4, 3/5

 

Answer 2. (C) if x ≤ y

Explanation:

I. x2 × 2161/3 = √576 x 22

x2 × 6 = 24 x 4

x2 = 16

x = ± 4

 

II. y3 – √1225 = √841

y3 – 35 = 29

y3 = 29 + 35

y3 = 64

y = 4

 

Answer 3. (E) if x = y or relationship between x and y can’t be established

Explanation:

I. 72x2 + 59x + 12 = 0

72x2 + 27x + 32x + 12 = 0

9x (8x + 3) + 4 (8x + 3) = 0

(8x + 3) (9x + 4) = 0

x = – 3/8, – 4/9

 

II. 44y2 + 67y + 15 = 0

44y2 + 55y + 12y + 15 = 0

11y (4y + 5) + 3 (4y + 5) = 0

(11y + 3) (4y + 5) = 0

y = – 3/11, – 5/4

 

Answer 4. (B) if x > y

Explanation:

[su_table responsive=”yes” class=”code”]

I. (
x
 4
 – 2) (
x
 3
 – 5) = 0

[/su_table]

[su_table responsive=”yes” class=”code”]

I. (
x -8
  4
) (
x – 15
   3
) = 0

[/su_table]

(x – 8) (x – 15) = 0

x = 8, 15

[su_table responsive=”yes” class=”code”]

II. √ × y2 =
49 × 3431/3
      √7         .

[/su_table]

[su_table responsive=”yes” class=”code”]

II. y1/2 × y2 =
72 × 7
   71/2  .

[/su_table]

y5/2 = 72 + 1 – 1/2

y5/2 = 75/2

y = 7

 

Answer 5. (A) if x < y

Explanation:

I. √484 x 13311/3 x X= 5082

22 x 11 x X = 5082

x = 21

[su_table responsive=”yes” class=”code”]

II.
 √ y 
 21
 +
 √ y 
  7
 = √ 16

[/su_table]

[su_table responsive=”yes” class=”code”]

 y  + 3√ y 
      2    
 = 4

[/su_table]

4√ y  = 84

 y  = 21

y = 441

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